odds on this poker scenario?

EXTRAPOLATER

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I've been playing poker for ex years but still consider myself a rookie at this hold-em stuff; played hold-em mildly for 5 or 6 years but used to play, in general, more than lately. Anywho...

I'm holding AK.
Oppenent sitting lower pair, say 88.

Who's favoured one-on-one.

Easy math for 1st card, at least (and subsequent be comparable barring a match), as I can pair-up at 12% (6 av. of 50 unseen cards) and opponent can pull trips at 4% (2 of 50 unseen, for him, obviously).

Who's favoured in this matchup and how is such calculated?

Pair likely favoured from the get-go but I'm not sure on that.
 
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dunclock

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well you are WAY off on your starting odds unless you are playing heads up and then there is 48 cards ... if you are playing 8 players then there is 36 cards left in the deck ... you have 3 chances if you play it all the way to the river with a flop, turn and river... the reason most people say that AK is 50% vs smaller pair is that you have 6 outs of the 3 aces and 3 kings then you multiply that by the 3 possible draw situations which would mean 18 of the 36 cards... but you cards odds greatly diminish after the flop ... AND this is based on PERFECT scenerio that none of the other 6 players out of the hand did not fold an ace or king also reducing your odds

simple odds are pretty easy if you are a math guy ... its number of outs times the number of draws divided by number of cards remaining

but simple odds do not factor in variables such as flushes or straights preflop
 

BobbyBlueChip

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well you are WAY off on your starting odds unless you are playing heads up and then there is 48 cards ... if you are playing 8 players then there is 36 cards left in the deck ... you have 3 chances if you play it all the way to the river with a flop, turn and river... the reason most people say that AK is 50% vs smaller pair is that you have 6 outs of the 3 aces and 3 kings then you multiply that by the 3 possible draw situations which would mean 18 of the 36 cards... but you cards odds greatly diminish after the flop ... AND this is based on PERFECT scenerio that none of the other 6 players out of the hand did not fold an ace or king also reducing your odds

simple odds are pretty easy if you are a math guy ... its number of outs times the number of draws divided by number of cards remaining

but simple odds do not factor in variables such as flushes or straights preflop

Send this to Cyndi and let me know what she comes back with
 

EXTRAPOLATER

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Thanks Snafu.

And dunclock, obviously first flip I get a flop, so 3 or /50, /49, /48, but I can't assume to know that my opponent doesn't hold one of A's or K's, so my unknowns are out of 50 (etc) on the flop, regardless of # of opponents.
Was thinking heads-up, howevas.

Think about a seven-card stud game where you're holding a 4-flush on card 6. Even at a full table you need to calculate your odds on your unknowns, being 46 cards with 9 possibly available flush-goals.
 

marine

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I've been playing poker for ex years but still consider myself a rookie at this hold-em stuff; played hold-em mildly for 5 or 6 years but used to play, in general, more than lately. Anywho...

I'm holding AK.
Oppenent sitting lower pair, say 88.

Who's favoured one-on-one.

Easy math for 1st card, at least (and subsequent be comparable barring a match), as I can pair-up at 12% (6 av. of 50 unseen cards) and opponent can pull trips at 4% (2 of 50 unseen, for him, obviously).

Who's favoured in this matchup and how is such calculated?

Pair likely favoured from the get-go but I'm not sure on that.

2 overcards vs a lower pair is considered to be a "coin flip" because it's so close to being 50/50. In truth, the pocket pair is ahead.

normally 53/47 or 54/46 -ish depending on the suits of the cards being held.
 
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