146.11
_______________
/I (b) I \
175.3 / I I \
/ I (h) I \ 104.96
/ I I \
/_(a)I___ ___(b) _____I_(c)\
199.0
darn...can't get my diagram to come out properly. anyways......the "/" is the hypotneuse of the triangles and the "I" it the side of the triangle.....you will have to drawn it out.
b = 146.11
and you know
a + b + c = 199.00
and you know the hypotenuse of the right triangle with sides a and h
a^2 + h^2 = (175.30)^2
and the hypotenuse of the right triangle with sides c and h
c^2 + h^2 = (104.96)^2.
So you need to use these equations to solve for a, c, and h.
I would start by using the second equation (and substituting b from
the first equation) to write c in terms of a. Then substitute that
into the last equation. Now you have two equations in a and h.
Subtract one of them from the other, and solve for a. Now substitute
back into either of the last two equations to get h.